Reformatted Data with Mean and Median Values

Answered using GPT 40 by GPT40

Question:

36 (25.7) * 7.47 (4.97)* 78# 27 (range 2- 50)# 8.2 (3)* 36 (range 6– 60)# 6.47 (range 2-29.8)# 21.8 (4.7)* 33# 20 (range 6- 72.5)* 12.3* 12 6 (range 6 months – 6 years)# 28,8* 30* 40.8 (27.6)* 10 (6)* 18 (range 12–36)* 61.4 (24.1)* 18,4 (range 6-120)* 8,5# 26,2# 36 24 24* 12 11(range 6–24) * 31.3# 12 12# 18.23 (13.15)* 12# 71# 110# 10.9 (3.6)* 14.2# 8.3 (3.6)* 12 12 41# 9,5# 12 12.3 (6.6)* 14 (3)*

*mean (Standard deviation); #median (Interquartile range)

Based on provided data, make this data to like this: if median: median= "number"(range) if mean: mean= "number"(Standard deviation)

Answer:

Here is the data reformatted according to your specifications:

mean= 36 (25.7) mean= 7.47 (4.97) median= 78 (range 2-50) mean= 8.2 (3) median= 36 (range 6–60) median= 6.47 (range 2-29.8) mean= 21.8 (4.7) median= 33 (range 6-72.5) mean= 12.3 median= 6 (range 6 months – 6 years) mean= 28.8 mean= 30 mean= 40.8 (27.6) mean= 10 (6) median= 18 (range 12–36) mean= 61.4 (24.1) median= 18.4 (range 6-120) median= 8.5 median= 26.2 mean= 24 mean= 12 median= 11 (range 6–24) median= 31.3 median= 12 median= 18.23 (13.15) median= 12 median= 71 median= 110 mean= 10.9 (3.6) median= 14.2 mean= 8.3 (3.6) mean= 12 median= 41 median= 9.5 mean= 12.3 (6.6) mean= 14 (3)