Calculation of Water Removed in Coconut Drying Process

A MECHANICAL DRYER IS DESIGN TO HUNDLE 2 METRIC TONS PER HOUR OF COCONUT NET CONTAINING 60 PERCENT WATER AND TO PRODUCE COPRA CONTAINING 5 PERCENT WATER. CALCULATE THE AMOUNT OF WATER REMOVED IN KG WATER BASED ON THE FINAL PRODUCT

To calculate the amount of water removed in the drying process, we need to follow these steps:

1. Determine the initial amount of water in the coconut meat:

   • The dryer handles 2 metric tons (2000 kg) of coconut meat per hour.
   • The coconut meat contains 60% water.

   [ \text{Initial water content} = 2000 , \text{kg} \times 0.60 = 1200 , \text{kg} ]

2. Determine the final amount of water in the copra:

   • The final product (copra) contains 5% water.
   • We need to find the mass of the final product (copra) first.

   Let ( x ) be the mass of the final product (copra) in kg.

   Since the mass of the dry matter remains the same before and after drying, we can set up the following equation:

   [ \text{Dry matter in initial coconut meat} = \text{Dry matter in final copra} ]

   The dry matter in the initial coconut meat is:

   [ \text{Dry matter} = 2000 , \text{kg} \times (1 - 0.60) = 2000 , \text{kg} \times 0.40 = 800 , \text{kg} ]

   The final copra contains 5% water, so it contains 95% dry matter:

   [ \text{Dry matter in final copra} = x \times 0.95 ]

   Setting the dry matter equal:

   [ 800 , \text{kg} = x \times 0.95 ]

   Solving for ( x ):

   [ x = \frac{800 , \text{kg}}{0.95} \approx 842.11 , \text{kg} ]

3. Calculate the final amount of water in the copra:

   [ \text{Final water content} = 842.11 , \text{kg} \times 0.05 \approx 42.11 , \text{kg} ]

4. Calculate the amount of water removed:

   [ \text{Water removed} = \text{Initial water content} - \text{Final water content} ]

   [ \text{Water removed} = 1200 , \text{kg} - 42.11 , \text{kg} \approx 1157.89 , \text{kg} ]

Therefore, the amount of water removed in the drying process is approximately 1157.89 kg per hour.